Web7 feb. 2024 · sec2θ - tan2θ = 1 Calculation: Given that, 6 + 8 tan θ = sec θ Multiply with 6 on both sides, 36 + 48 tan θ = 6sec θ ---- (1) Also, we have 8 - 6 tan θ = k sec θ Multiply with 8 on both sides, 64 - 48 tan θ = 8k sec θ ----- (2) Adding equation (1) & (2), we get 36 + 48 tan θ + 64 - 48 tan θ = 6sec θ + 8k sec θ ⇒ 100 = sec θ (6 + 8k) WebIf tantheta = mn , show that msintheta-ncosthetamsintheta+ncostheta = m^2 - n^2m^2 + n^2 . Question If tanθ= nm, show that msinθ+ncosθmsinθ−ncosθ= m 2+n 2m 2−n 2. Easy Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions If acosθ+bsinθ=p, asinθ−bcosθ=q prove that a 2+b 2=p 2+q 2. Hard View solution >

Find the Other Trig Values in Quadrant III tan(x)=21/20 Mathway

Web15 mei 2024 · Given: tanθ = \(\frac{20}{21}\), show that \(\frac{1 - sinθ + cos θ}{1 + sinθ + cos θ} = \frac{3}{7}\) Since tanθ = perpendicular / base . So we construct a right triangle ABC right angled at C . such that ∠ABC=θ and AC = Perpendicular = 20. BC = base = 21. By Pythagoras theorem,AB 2 = AC 2 + BC 2. ⇒ AB 2 = (20) 2 + (21) 2. ⇒ AB 2 ... http://amsi.org.au/teacher_modules/The_trigonometry_functions.html prbc holdings ltd

if tan theta equals to 20/21 show that in a (1- sin theta + cos theta ...

WebIf tanA=20/21 show that 1-sinA+cosA/1+sinA+cosA if tan theta =20/21 show that 1+sin theta Aristotle's Wheel Paradox - To Infinity and Beyond Up and Atom 2M views 2 years … WebIf tan θ= 20 21, show that (1−sinθ+cosθ) (1+sinθ+cosθ) = 3 7. Solution Let us consider a right Δ ABC right angled at B Now it is given that tanθ= AB BC= 20 21 So, if AB = 20k, … WebIf tan θ = 20/21, show that Answer: Given: tan θ = 20/21 tanθ = 20k/ (21k) Where k is any positive. By Pythagoras theorem: AC^2 = AB^2 + BC^2 = 441k^2 + 400k^2 AC = 29k … scooby doo mixed drink recipe